7b^2+6=181

Solution for 7b^2+6=181 equation:

7b^2+6=181

We move all terms to the left:

7b^2+6-(181)=0

We add all the numbers together, and all the variables

7b^2-175=0

a = 7; b = 0; c = -175;
Δ = b2-4ac
Δ = 02-4·7·(-175)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-70}{2*7}=\frac{-70}{14}
=-5
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+70}{2*7}=\frac{70}{14}
=5
$